Y=-0.04x^2+0.75x+0.01

Solution for Y=-0.04x^2+0.75x+0.01 equation:

=-0.04Y^2+0.75Y+0.01

We move all terms to the left:

-(-0.04Y^2+0.75Y+0.01)=0

We get rid of parentheses

0.04Y^2-0.75Y-0.01=0

a = 0.04; b = -0.75; c = -0.01;
Δ = b2-4ac
Δ = -0.752-4·0.04·(-0.01)
Δ = 0.5641
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.75)-\sqrt{0.5641}}{2*0.04}=\frac{0.75-\sqrt{0.5641}}{0.08}
$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.75)+\sqrt{0.5641}}{2*0.04}=\frac{0.75+\sqrt{0.5641}}{0.08}
$